P
(
A
)
=
∑
P
(
{
(
e
1
,
…
,
e
N
)
}
)
=
(
N
k
)
⋅
p
k
q
N
−
k
P(A) = \sum P(\{ (e_1,\dotsc,e_N) \}) = \binom{N}{k} \cdot p^kq^{N-k}
P
(
A
)
=
∑
P
(
{
(
e
1
,
…
,
e
N
)
}
)
=
(
k
N
)
⋅
p
k
q
N
−
k
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